Let Q = water flow rate (ft3/min)
d = diameter of the first barrel (ft)
h = height of the first barrel (ft)
V1 = volume of first barrel = (pi*d2*h)/4 (ft3)
V2 = volume of the second barrel = pi*(2d)2*(2h) = (2*pi*d2*h) (ft3)
Then, T1 = Time to fill first barrel = V1/Q = (pi*d2*h)/4Q (min)
T2 = Time to fill second barrel = V2/Q = (2*pi*d2*h)/Q (min)
The ratio T1/T2 = 1/8 or T2 = 8T1