
John M. answered 04/25/20
Math Teacher/Tutor/Engineer - Your Home, Library, MainStreet or Online
Cos(11π/12) = -0.965925 x 180/π = -55.343°
Using Cos(Θ/2) = ±√( [1 + Cos(Θ)] / 2 )
Cos([11π/6)]/2) = -0.965925 x 180/π = -55.343°
Kenna A.
asked 04/24/20John M. answered 04/25/20
Math Teacher/Tutor/Engineer - Your Home, Library, MainStreet or Online
Cos(11π/12) = -0.965925 x 180/π = -55.343°
Using Cos(Θ/2) = ±√( [1 + Cos(Θ)] / 2 )
Cos([11π/6)]/2) = -0.965925 x 180/π = -55.343°
Yefim S. answered 04/25/20
Math Tutor with Experience
cos(11π/12) = - cos(π/12) = - sqrt((1+ cos(π/6))/2) = - (1 + sqrt(3))/2)1/2 = - (2 + (3)1/2)1/2/2
Get a free answer to a quick problem.
Most questions answered within 4 hours.
Choose an expert and meet online. No packages or subscriptions, pay only for the time you need.