Denise G. answered • 04/24/20

Algebra, College Algebra, Prealgebra, Precalculus, GED, ASVAB Tutor

6x^{2}-60x+438 Factor out a 6 from the first 2 terms.

6(x^{2}-10x )+438 Do (b/2)^{2} to find the c term. (-10/2)^{2 }= 25

6(x^{2}-10x+25)+438-150 Adding 25 inside the parenthesis is really like adding 6(25)=150 to that side of the equation. To keep the equation in balance, you have to subtract 150 from the other term. Simplify

**6(x-5)**^{2}**+288**