
David L. answered 04/24/20
Very Experienced Algebra Tutor and Instructor
The area of a rectangle is Length x Width
A = L x W
A = 80
L = x-3
W = x-5
A = (x-3)(x-5)
80 = x2 - 8x + 15 [FOIL the quadratic]
0 = x2 - 8x - 65 [Subtract 80 from each side]
0 = (x-13)(x+5) [factor the quadratic]
Therefore x = 13 or x = -5
We must now check to make sure the length and width make sense based on the x values in the solution
When x=13
L = 13-3 = 10
W = 13-5 = 8
A = (10)(8) = 80 This checks out
When x = -5
L = -5-3 = -8
W = -5-5 = -10
We can't have negative width and length, so x=-5 is not a valid solution.
Therefore the only solution for x is x=13