Nasir M. answered 04/23/20
Physics, Chemistry and Mathematics Tutor
a+o = $5.3 ----------- (1)
2a + 2o = $14 -------(2)
divide equ (2) by 2
(2a + 2o) / 2 = $14 / 2
a + o = $7 which contradicts equ (1)
therefore no solution exist ---
Gin L.
asked 04/23/20Nasir M. answered 04/23/20
Physics, Chemistry and Mathematics Tutor
a+o = $5.3 ----------- (1)
2a + 2o = $14 -------(2)
divide equ (2) by 2
(2a + 2o) / 2 = $14 / 2
a + o = $7 which contradicts equ (1)
therefore no solution exist ---
a + o = 5.3
2a + 2o = 14
Well, we can divide the 2nd equation by 2.
a + o = 7
Well, if a + o = 7, it can't also equal 7, so no.
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