Patrick B. answered 04/23/20
Math and computer tutor/teacher
0=
dC/dt=
[7(t^3 + 27) - (7t)(3t^2)] / (t^3 + 27)^2
the denominator cancels, not a factor, and irrelevant
[7(t^3 + 27) - (7t)(3t^2)] = 0
7 t^3 + 27*7 - 21t^3 = 0
-14t^3 + 189 = 0
2t^3 - 27 = 0
t^3 = +27/2
t = +3 / 2^(1/3)
= +3 * 2^(2/3) / 2
= (-3/2)(2^(2/3))
APPROXIMATELY (2.381, 0.41)



