Hi I need help with a delta math question

Question

If f(x)=5x^3-39x^2+27x+7 and x-7 is a factor of f(x), then find all of the zeros of f(x) algebraically.

Answer 1

Simply divide f(x)=5x^3-39x^2+27x+7 on (x-7) and you will get 5x² - 4x -1, solve one for x and you have x1= 1, x2 = - 1/5.

You also have a third zero x3 = 7 from a factor at the problem condition.