If sin(theta)=4/5 and theta is in quadrant 2,the value of cot(theta) is...? (Write as fraction if needed).

Question

2.) If sin(theta)=4/5 and theta is in quadrant 2,the value of cot(theta) is...?
(Write as fraction if needed).
I don't understand this, but I tried.

If sin of theata=4/5, then I know the hypotenuse is 5. I then assumed that this would be a 3,4,5 triagle. Cot=cos(theta)/sin(theta). I got 0.75. (3/4).
I don't know if 3/4 is correct. Also, it's in quadrant 2...would that mean -3/4? I am all over the grid lost here. I tried to solve this problem but I really don't know how or what steps to take. I'm not positive in my answer. I feel like my answer is probably incorrect.

Answer 1

cot=cos/sin

cot=(-3/5)/(4/5)=-3/4

cos is negative in the second quadrant while sin is positive in the second quadrant

-/+=-