What is the value of k?

Question

The GCF of x³y^k and x^2ky⁴ is x³y³

Answer 1

For variable x, the GCF of x^3 and x^(2k) is x^3

So then 2k>=3 ---> k>=3/2

For variable y, the GCF of y^k and y^4 is y^3, so k=3

So k>=3/2 and k=3

It's safe to say that k=3