algebra question

Question

A company offers two different plans for high-speed video transfers. Plan A charges a $10 monthly fee plus 5 cents per transfer. Plan B charges a $25 monthly fee plus 2.5 cents per transfer. After how many transfers does the second plan become less money for that month?

Answer 1

10 + .05x = 25 + .025x

We make the two deals equal to each other and then solve for x. Solve for x and you get 600. Hope this helps!

Answer 2

1000+5x=2500+2.5y

5x-2.5y=1500

Answer 3

A: y = 5x + 10

B: y = 2.5x + 25

2.5x + 25 < 5x + 10

-2.5x < -15

x > 6

The company will need more than 6 transfers in order for Plan B to be cheaper than Plan A.

Answer 4

A: y = 5x + 10

B: y = 2.5x + 25

2.5x + 25 < 5x + 10

-2.5x < -15

x > 6

The company will need more than 6 transfers in order for Plan B to be cheaper in price compared to Plan A.

Answer 5

25 + 0.025t < 10 + 0.05t

Can you solve for t and answer?

Answer 6

Let x = number of transfers

Plan A: y=10+0.05x

Plan B: y=25+0.025x

If you want to know when Plan B is less,

Plan B < Plan A

25+0.025x < 10+0.05x

Can you solve the equation for x?