CRUZ C. answered 04/16/20
Experienced Math Dept Chair, 7+ Years of Teaching Experience
The area of a triangle is 1/2 (base)(height).
Given that the height of the triangle is 6 less than the base you can write that mathematically as
h = b-6.
In the equation for the area of a triangle (A= 1/2*b*h), you can then replace the variable for height (h) with the equation that you created to represent the 'Given' part of the problem.
A = 1/2 (b) (h)
A = 1/2 (b) (b-6)
A = 1/2(b2-6b)
Because the question asks you to write an equation using x as your variable and only x, you can replace the variable b with x, understanding that the variable x represents the length of the base, b.
A = 1/2 (x2 - 6x)
KYRA R. ASKED A FOLLOW UP QUESTION:
How would I solve for x in that equation?
My response:
Part of the problem indicates that the area of the triangle is 80 inches squared. Using the equation A = 1/2 (x2 - 6x), I would substitute the variable A for area with the actual area, which is 80cm2.
80cm2 = 1/2 (x2 - 6x)
To solve this quadratic equation, I would multiply both sides of the equation by 2.
2(80) = 2(1/2)(x2 - 6x)
160 = x2 - 6x
Then I would subtract 160 from both sides of the equation:
160-160 = x2 - 6x -160
0 = x2 - 6x -160
Now factor to solve for the values of x that make this equation equal to zero.
0 = (x-16)(x+10)
x-16 = 0 or x+10 = 0
x=16 or x = -10
Both values 16 and -10 are correct solutions if we were only solving this algebraic equation; however, the problem is a real world application that includes a triangle.
Recall from the beginning of the problem how I mentioned:
"understanding that the variable x represents the length of the base.'
The two solutions which represent the length of the base of the triangle are 16 and -10.
The base of the triangle has a length of 16 or -10; only one of these is correct. You cannot have a negative distance. For example, we could say that we drove 25 miles to the local animal shelter to adopt a puppy; we would NOT say that we drove negative 25 miles to the local animal shelter to adopt a puppy.
Thus the solution: x = 16; always check your solution if time permits.
A = 1/2 (b) (b-6)
80 = 1/2 (16) (16-6)
80 = (8) (10)
80 = 80 (true? if yes, your solution is correct)
Thank you Kyra! If you have any additional questions, please reach out to me.
All the best!
CRUZ C.
Kyra asked a follow up question: How would I solve for x in that equation? My response: Part of the problem indicates that the area of the triangle is 80 inches squared. Using the equation A = 1/2 (x2 - 6x), I would substitute the variable A for area with the actual area, which is 80cm2. 80cm2 = 1/2 (x2 - 6x) To solve this quadratic equation, I would multiply both sides of the equation by 2. 2(80) = 2(1/2)(x2 - 6x) 160 = x2 - 6x Then I would subtract 160 from both sides of the equation: 160-160 = x2 - 6x -160 0 = x2 - 6x -160 Now factor to solve for the values of x that make this equation equal to zero. 0 = (x-16)(x+10) x-16 = 0 or x+10 = 0 x=16 or x = -10 Both values 16 and -10 are correct solutions if we were only solving this algebraic equation; however, the problem is a real world application that includes a triangle. Recall from the beginning of the problem how I mentioned: "understanding that the variable x represents the length of the base.' The two solutions which represent the length of the base of the triangle are 16 and -10. The base of the triangle has a length of 16 or -10; only one of these is correct. You cannot have a negative distance. For example, we could say that we drove 25 miles to the local animal shelter to adopt a puppy; we would NOT say that we drove negative 25 miles to the local animal shelter to adopt a puppy. Thus the solution: x = 16; always check your solution if time permits. A = 1/2 (b) (b-6) 80 = 1/2 (16) (16-6) 80 = (8) (10) 80 = 80 (true? if yes, your solution is correct)04/17/20
CRUZ C.
The Comments section does not appear to retain the formatting which enhances readability; however the solution posted in the Expert Answer section retains some formatting. Thus I direct your attention to the line item which reads 'KYRA R. ASKED A FOLLOW UP QUESTION:' The solution to the follow up question begins there.04/18/20
Kyra R.
Thank you! And how would I solve for X in that equation?04/17/20