What are the excluded values of n2-2n-24/n2+2n-8

Answer 1

I assume you meant the ratio to be (n² - 2n - 24)/(n² + 2n - 8). (Use parentheses in this forum.) Factor both polynomials and see if there is a value of where you divide by zero.

(n² - 2n - 24)/(n² + 2n - 8) = (n - 6)(n + 4) / [(n - 2)(n + 4)]

Note the denominator is zero when x equals 2 or -4. These are excluded values. Note also that (n+4) would cancel out, but that operation assume n ≠ -4.