Patrick B. answered 04/15/20
Math and computer tutor/teacher
f(x) = C * b^x
(2,12) ---> f(2) = 12 ---> 12 = C * b^2
(5,96) ---> f(5) = 96 ----> 96 = C * b^5
But 96 = 12 * 8
C * b^5 = 8 * C * b^2
b^5 = 8 * b^2
b^3 = 8
b = 2
Per first equation: 12 = C * b^2
12 = C * 2^2
12 = 4 C
C = 3
f(x) = 3 * 2^x