Ahmad B. answered 05/10/20
PhD in Electrical Engineering (15+ years tutoring Algebra 1)
To find the image of $v$ all you have to do is pass $v$ to the input of $T$ as
1) $T(v1,v2) = T(3,-14) = (3-14,3+14) = (-11,17) $
2) $T(v1,v2) = T(2,3,0) =(3-2,2+3,2(2)) = (1,5,4) $
To find the pre-image of w is a bit more challenging as you need to figure out which input produces $w$
1)so say for $ w= (3,19)$ you have to find which v gives
v1+v2 = 3
v1-v2= -14
Add both equations to get v1 as 2v1 = -11 so v1 = -5.5 and v2 = 3-v1=3+5.5=8.5. So we can say that the preimage of w is (-5.5,8.5)
2) Same methodology could be followed to get v1,v2,v3 that satisfy
v2-v1=-11
v1+v2=-1
2v1 = 10
From the last equation v1 = 5 hence from the second equation we get that v2 = -1 - v1 = -6 so note that we have solved the equation with v3 so for any v3 the preimage is (5,-6,v3)