(3^-2-2^-2)^-2

Question

 the directions is to simplify completely 

Answer 1

Hi Cass,

 

(3^-2 -2^-2 )^-2

 

<=> [(1/3)² - (1/2)²]^-2   notice how the inside is a difference of two squares a²-b²=(a+b)(a-b)

 

<=> [(1/3+1/2)(1/3-1/2)]^-2

 

<=>  [(5/6)(-1/6)]^-2

 

<=> (-5/36)^-2

 

<=> (36/5)²

 

I hope this helps