# Probability Question

A six sided dice and 20 sided dice are rolled.

Let event A be rolling and odd number, and event B be rolling a multiple of on the 20 sided dice.

Determine P(A∩B)

Choices:

-1/120

-7/10

-1/20

-1/10

Patrick L.

tutor
In event B, what number is the multiple that you are looking for on the 20-side die.
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04/11/20

James G.

oops my bad. Its multiples of 4
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04/11/20

Martin S.

Okay, I see your clarification , and again, if the total of the dice must be odd, and the number on the 20 sided die must be a multiple of 4, then only 1, 3 and 5 need to be considered on the 6 sided die. P(1.3.or 5) on d6 = 1/2 5 numbers on d20 are multiples of 4, so that probability is 5/20 = 1/4. Multiplying those two probabilities gives 1/2 x 1/4 = 1/8, and not one of the choices. Is there information missing?
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04/13/20

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