Sanjay S. answered 02/03/15
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Sofia,
For 1.
5(3x-4) -10x < 4(2x-1) -16
Simplify
5*3x -5*4 -10x < 4*2x -4*1 -16
15x -10x -20 < 8x -4 -16
5x -20 < 8x -20
Add 20 to both sides
5x<8x
Subtract 5x from both sides
0<3x
or 3x> 0
x > 0
For second equation
-4<2b-6<8
So -4< 2b-6
Add 6 to both sides
2<2b
Divide by 2
1<b
Also 2b-6 < 8
2b<14
b <7
Combining both we get 1<b<7
b is between 1 and 7