how many gallons of 70% antifreeze solution must be mixed with 60 gallons of 30% antifreeze to get a mixture that is 60% antifreeze

Answer 1

x = number of gallons of 70% mixture

60 gallons of 30% mixture

x + 60 = total number of gallons of 60% mixture

70x + 30(60) = 60(x + 60)

Solve for x.

70x + 1800 = 60x + 3600

10x = 1800

x = 180 gallons