Ron Swanson has $5.20 in his piggy bank made up of dimes and quarters. He has a total of 28 coins. How many of each coin does he have?

Answer 1

This equation can be solved using two equations. We know that a dime is 10 cents and a quarter is 25 cents, and the total amount of money in this problem is 520 cents.

If x = number of dimes and y=number of quarters, our two equations should be,

10x + 25y = 520

x + y = 28

We can then solve for x in the second equation by subtracting y from each side. We now have x = 28 - y. This can now be plugged into the first equation for x.

10(28-y) + 25y = 520

280 - 10y + 25y = 520

15y = 240

y = 16

As y = 16, we know that we have 16 quarters. Plugging 16 in for y, we now have the equation

x + 16 = 28

x = 12

We have now solved for the number of dimes. The solution for this problem is 16 quarters and 12 dimes.

To check our solution, we can plug these values into the first equation.

12(10) + 25(16) = ?

120 + 400 = 520, which is $5.20.

Hope this explanation is helpful, and please reach out with more questions!

Answer 2

Ron has 16 quarters and 12 dimes. Use a system of linear equations to obtain the results.