How many liters of ammonia gas (NH3) can be formed from the reaction of 150. L of H2?

Answer 1

Ammonia is formed by combining H₂ and N₂ in the following balanced equation:

3H₂ + N₂ = 2NH₃

To solve the equation use stoichiometry using the balanced equation above. Moles will cancel to leave the answer in liters as follows:

150L H₂ * 2 moles NH₃ / 3 moles H₂ =100L NH₃

Hope it helps!

Answer 2

2N₂ + 3H₂ ==> 2NH₃

150 L H₂ x 2 L NH₃/3 L H₂ = 100 L NH₃ assuming N₂ is not limiting