J.R. S. answered 04/08/20
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q = heat
Ccal = heat capacity of the calorimeter = 1265 J/ºC
∆T = change in temperature = 25.12 - 22.34 degrees = 2.78ºC
q = Ccal x ∆T = 1265 J/ºC x 2.78ºC
q = 3517 J