Enter the slope-intercept of the line that has the same slope as y-3=1/2(x+3) and contains the point (8,4). Complete the explanation of how you found the equation.

Question

y=____; I used the general form of a line in slope-intercept form, or y-y₁=m(x-x₁), y=mx+b, ax+by=c (choose 1 of the 3). The slope, m, is____. Then I substituted _____ for x and _____ for y into the standard form and solved for b, which is _____.

(I need help as soon as possible pls fill the blanks)

Answer 1

Think about solving the equaiton y= mx + b.

By doing so you will first solve the distributive property on the right side of the equaiton

1/2(x + 3) = 1/2x + 3/2. Then you will ADD the constant -3 to both sides of the eqaution. Make sure tochane 3 to 3/3, and ADD 3/3 to the constant 3/2 by finding a common denominator. The common denominator = 6

making 9/6 + 6/6 = 15/6

y -3 = 1/2x + 3/2

+3 +3

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y = 1/2x + 15/6

Now take your slope(m) = 1/2x and use the point (8,4) to substitute into the equation.

x, y

y = 1/2x + b

4 = 1/2(8) +b

4= 4 + b

-4= -4

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0 = b

y = 1/2x

y = 1/2 x; I used slope interecept equaiton y = mx + b; then I substittued 8 for x and 4 for y and solved for b = 0.

Answer 2

Your notation is unclear, but I assume your mean y-3=(1/2)(x+3) [which is NOT what you wrote!]

The slope of this line is 1/2.

The equation of the line with this slope through (8,4) is

(1/2) = (y-8)/(x-4)

I will leave it to you to "massage" the equation into slope intercept form.