An apple is dropped from a height of 64 The function h = - 16t ^ 2 + 64 gives the height of the apple after seconds. a. Graph the function . b . When does the apple hit the ground ?

Answer 1

a. Your starting point, along the y-axis, is where t = 0.

-16(0²) + 64 = 64, so your starting point is at (0,64).

After 1 second, you're at -16(1²) + 64 = 48

When it hits the ground, the height = 0.

-16t² + 64 = 0

I am going to divide both sides by -1.

0 = 16t² - 64

Hey, now we have the difference of squares!

0 = (4t + 8)(4t - 8)

4t + 8 = 0

4t = -8

t = -2

Well, we can't go back in time, so we disregard this answer.

4t - 8 = 0

4t = 8

t = 2 seconds

Your ending point will be (2,0)