Flora M.

asked • 04/07/20

Cooling/Heating Pad Chemistry Question

Hi I need help with someone to check if I have solved the following correctly :) Thanks in advance



Question

An cooling pad or heating pad in "pocket format" can conceivably consist of a plastic bag divided into 3 partitions. When the pad is squeezed hard enough, the partitions break apart and the solid X is mixed with water and dissolved.


X (s) + H2O -----------> X (aq)


ΔH = +58 kJ / mole X


Data available: 0,1 moles of solid X is in total available in one each pad. The volume of the water in the pad is 0,1 dm^3. Assume that the volume does not change when X is mixed with the water.


a) Is the mentioned pad a heating or cooling pad?


b) The partitions containing contents has been at room temperature (20 ° C) before use. Calculate the temperature change when the partitions are broken. The solution formed has a density of 10.5 g / cm³. The specific heat capacity of the solution is 4.2 J / g · K. You can assume that the volume does not change when the substance X is dissolved.


c) How big would the heat change be if the pad was stored in a refrigerator (8 ° C) before it was used?


Answer:

a) It is a cooling bag. Since delta H is positive, energy is taken from the surroundings in order for the reaction to happen, therefore the surroundings will be cooler.


b) E= m*c*delta T

To calculate E i use the fact that delta H is 58 000 J/mole of X and that I have used 0.1 moles of X during the reaction. Therefore the E used for the reaction is 58 000* 0.1=5800 J

c= 4.2 J/(g*K)

To calculate m, 0.1 dm^3 solution is equal to 100 cm^3 which can be multiplied with the solutions density of 1.05 g/cm^3= 105 g


Now I have all the data needed to calculate

delta T= E/(m*c)

delta T= 5800/ (105*4.2)= 13.2 K


Answer to question b)= The temperature change is 13.2 Kelvin


c) It doesnt matter what the starting temperatute is?? (However it is possible for the pad to freeze, because the end temperature will be somewhere below 0, and the freezing process is exothermic, energy will be released, but I am not sure if this is something that is important to take into consideration here)


J.R. S.

tutor
Where did you come up with 0.1 moles of X and where did you come up with 0.1 dm3 (100 ml) as a volume? Also, why did you report the answer in degrees K when the problem states degrees C? When using ∆T it doesn't matter, so your answer should be in ºC. Specific heat of 4.2 J/g-K is the same as 4.2 J/g-C
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04/07/20

Flora M.

Hi, Ah i am so so sorry I forgot to add the data list, the 0,1 moles and 0,1 dm^3 is stated there. The only data missing was delta T, which can be calculated with all given data, which is the number of moles, volume and everything else mentioned in the question above Regarding answering in which degree unit, I always tend to use Kelvin when at these problems, but I see your point (as well as understand it) Thank you,
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04/07/20

Flora M.

I have now added the data above in my question :)
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04/07/20

1 Expert Answer

By:

Flora M.

Thank you so much!! I just wonder, regarding c), since the initial temperature is 8 degrees Celsius and the change is 13.2 degrees Celsius. The final temperature will be -5.2 degree Celsius. However, if the water solution with the salt with freeze around 0 degrees Celsius, then energy would be released during the freezing process since it is exothermic. Wouldn't that make the final temperature a little higher than -5.2 degrees Celsius and therefore the temperature or heat change is different?
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04/07/20

J.R. S.

tutor
First, the heat change can't be different unless you change the mass or the specific heat, neither of which have changed. Since it is an endothermic reaction heat is put into the system so the temperature of the system will increase, not decrease. Does this makes sense, or am I missing something?
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04/07/20

Flora M.

Ah yes that makes sense So it is like this?: The initial temperature of the whole pad when it is in the fridge is 8 deg. Celsius. And the system itself with the solution will increase 13.2 degrees Celsius, but that means the heat needed to make it increase that much is taken from the surroundings, which means the temperature of the surroundings will decrease 13.2 degrees and that is why the pad feels cold when this happens?
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04/07/20

J.R. S.

tutor
Yes, but I'd say that is why the surroundings (the pad, your skin if touching the pad, etc) feels cooler. But yes, you are correct.
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04/07/20

Flora M.

Ok thank you, yet again hehe, very much :)
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04/07/20

J.R. S.

tutor
No problem. My pleasure.
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04/07/20

Flora M.

Hi I just wonder something: What if the temperature change will be less in c) because when the water is colder (8 deg.), less salt with solute itself with water and therefore less energy taken up during the reaction?
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04/08/20

Flora M.

I also wonder if Le Chatliers principle can be used in the c) question?
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04/08/20

Flora M.

Oh nevermind Le Chatliers is about equilibrium shifting but I do not think that is needed for this question However I still do wonder if the temperature of the water affects the solubility and therefore the energy released/temperature change
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04/08/20

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