Mark M. answered 04/07/20
Retired math prof. Calc 1, 2 and AP Calculus tutoring experience.
Total distance = 15 + 15(3/5) + 15(3/5)2 + ...
This is a geometric series with common ratio r = 3/5. Since r lies in the interval (-1,1), the series has a finite sum, S.
S = a1 / (1-r) = 15 / (1-3/5) = 15(5/2) = 75/2 = 37.5"