Denise G. answered 04/06/20
Algebra, College Algebra, Prealgebra, Precalculus, GED, ASVAB Tutor
First, we need the slope of the line given. So manipulate the equation until it is in the y=mx+b form
2y-4x=6 Add 4x to both sides
2y-4x+4x=6+4x Simplify
2y=4x+6 Divide by 2
2y/2=4x/2+6/2 Simplify
y=2x+3
Since the slope of line is 2, the slope of the line parallel to is is also m=2. To find the equation of the line going through the point (3,0) use the following equation.
(y-y1)=m(x-x1) Plug in known values
(y-0)=2(x-3) Distribute
y=2x-6