How do I solve the rate of change for this equation?

Question

Answer 1

How do I solve the rate of change for this equation?

rate of change is slope.

so write in a slope form:

Recall y=mx+b, where m is slope

y=0.5(x-2)+6

y=0.5x+5

m=0.5 (rate of change is 0.5 )

meaning when x change by 1, y change half of 1,which is 0.5, compared to previous y value.

ex:

when x=0, y=5

when x=1, y=5.5

when x=2, y=6

when x=3, y=6.5

when x=4, y=7

you see pattern here? when x increase by 1, y increase by 0.5, which is half of 1.

let us test another value:

when x=4, y=7

when x=8, y=9

when x=12, y=11.

you see pattern here? when x increase by 4, y increase by 2, which is half of 4.

I hope this helps.

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Answer 2

The rate of change would be the slope for this equation, so we need to first rewrite the equation in slope-intercept form. Eliminating the parentheses and isolating the "y", the equation now becomes y = .5x + 5. The slope is the coefficient for the x term, so the slope is .5.