A bag contains 6 Red, 4 Blue, and 10 Green marbles. Two marbles are drawn, without replacement. What's the probability of drawing a Red and then a Blue marble?

Question

A bag contains 6 Red, 4 Blue, and 10 Green marbles. 

Two marbles are drawn, without replacement. 

What's the probability of drawing a Red and then a Blue marble?

Answer 1

6 RED marbles

4 BLUE marbles

10 GREEN marbles

________________

20 marbles

WITHOUT REPLACEMENT:

Probability of drawing a RED marble on the 1st draw = 6/20 = 3/10 = .3

Probability of drawing a BLUE marble on the 2nd draw = 4/19 = .2105

Therefore, the probability of drawing a red then a blue marble, without replacement

is: (.3) (.2105) = .06315 = 6.315%

ANSWER: 6.315% or you could round off and say 6.3%

Hope this was helpful Nawal.