
Jack L. answered 04/02/20
Princeton PhD Student, Yale Graduate, and Experienced Tutor
Let us call the first number x. Then, the second number is x + 2 (i.e. if the first number was 1, the next consecutive odd is 1 + 2 = 3). Thus, we can write that the product of the two numbers is 143 algebraically as x(x + 2) = 143. We can then solve this equation by factoring as follows:
(1) x(x + 2) = 143
(2) x2 + 2x = 143
(3) x2 + 2x - 143 = 0
(4) (x - 11)(x+13) = 0
(5) x = 11, x = -13
Where we set each expression in parenthesese from step 4 equal to 0. Presumably, we are only interested in positive values of x here. Thus, our two values are 11 and 11 + 2 = 13. We can then verify that 11 and 13 are in fact two consecutive odd numbers, and that their product is 143. I hope this helps!

Jack L.
Hi Noah, I am unable to see the other question you have listed here! However, I would be very happy to set up a session with you to go over the material if that would be helpful. Thanks so much! Best, Jack04/02/20
Noah Z.
thank you so much! do you think you could do the other question i have listed?04/02/20