Write an equation for a line perpendicular to y = − 5 x + 5 and passing through the point (10,3)

Answer 1

y = mx + b

The slope of the perpendicular line must be the negative reciprocal of the slope of the given line, so

m = -(1/-5) = 1/5

y = (1/5)x + b

Use the given point to find b.

3 = (1/5)(10) + b

Solve for b and finish from here. Use this same reasoning to solve similar problems that you posted. (In the case of parallel lines, the slopes are the same.)