A ball is thrown into the air with an initial upward velocity of 60 ft/s. It’s height (h) in feet after t seconds is given by the function h=-16t^2+60t+6. What will the height be at t=3 seconds?

Question

A)35 feet

B)40 feet

C)42 feet

D)45 feet

Answer 1

To solve this, plug in t=3 into the equation and solve.

h=-16(3)²+60(3)+6 = 42 ft