Can anyone solve the algebra problem?

Question

If 4x-y = 12, then what is the value of:

16 ^x

^____ ?

2 ^y

Choices:

(A) 8

(B) 2 ¹⁰

(C) 2 ¹²

(D) 2 ¹⁶

Answer 1

4x-y = 12 Solve this for y, Add y to both sides and subtract 12 from both sides.

y=4x-12 Substitute into the second equation

16^x/2^4x-12 Rewrite the numerator so it has a like base to the denominator (16=2⁴)

2^4x/2^4x-12 To divide exponents with like bases, the exponents subtract

2^4x-(4x-12) Distribute

2^4x-4x+12 Combine like terms

2¹² (C)

Answer 2

16^x = 2^4x

16²/2^y = 2^4x-y = 2¹²