He B.

asked • 03/29/20

Calorimetry: How to Find Heat Lost?

In Part 1 of the lab you will test how well a coffee cup calorimeter matches the ideal case. You will do this by adding a known mass of warmer than room temperature water (at a known temperature) to a known mass of water at room temperature in the calorimeter. The relevant equations are:

“heat lost” = (mhot water)(cwater)(ΔThot water)
“heat gained” = (mroom temp water)(cwater)(ΔTroom temp water) + qcalorimeter
where:
qcalorimeter = (calorimeter constant)(ΔTcalorimeter)
ΔTcalorimeter = ΔTroom temp water

As long as we use the same calorimeter, we do not need to know the mass of the calorimeter (the calorimeter constant is the product of the mass of the calorimeter and the heat capacity of the calorimeter). Ideally, the calorimeter constant would have a value of 0 J/°C. Consider the following data and answer the questions below.

When 50.0 mL of 60.0°C water was mixed in the calorimeter with 50.0 mL of 25.0°C water, the final temperature was measured as 41.1 °C. Assume the density for water is 1.000 g/mL regardless of temperature.

a. Determine the magnitude of the "heat lost" by the hot water. Do not enter a sign.

 J


1 Expert Answer

By:

Still looking for help? Get the right answer, fast.

Ask a question for free

Get a free answer to a quick problem.
Most questions answered within 4 hours.

OR

Find an Online Tutor Now

Choose an expert and meet online. No packages or subscriptions, pay only for the time you need.