What is an equation of the line that passes through the points (-3,1) and (-6,6)? Put your answer in fully reduce form

Answer 1

First find slope. m = (y₂ - y₁)/(x₂ - x₁) = (6 -1)/(-6 --3) = 5/-3

then. use. y - y₁ =. m (x - x₁). which gives. y - 1 = -5/3(x - 3)

then. y - 1 = -5/3x + 5

then y = -5/3 x + 6. or. 5x + 3y = 18