5x^2-3x-5=0 rounded to the nearest hundredth

Answer 1

5x² - 3x - 5 = 0 is a quadratic equation that we would first attempt to solve by factoring. If I could factor this, it means I would need to find two numbers that would multiply to give -25x² but add to get -3x and there are no two numbers that do that so it is not factorable. That means I would need to use the quadratic formula to solve.

The quadratic formula for ax² + bx + c = 0 is x = [-b ± √(b² - 4ac)]/(2a)

a = 5

b = -3

c = -5

So, plugging in the numbers we get:

x = [-(-3) ± √((-3)² - 4(5)(-5))]/(2(5)) = [3 ± √(9 + 100)]/10 = (3 ± √109)/10 = 13.44/10 and -7.44/10

So x = 1.34 and x = -0.74

Answer 2

X= 3.13 and X= -.74

Answer 3

For this problem we will have to factor in order to solve for x. We can do this using the quadratic formula:

x= (-b±√(b² - 4ac))/ (2a)

x = (3±√(-3² - 4(5)(-5)) / 2(5)

x = (3 ±√(9 + 100)) / 10

x = (3 ± 10.44) / 10

At this point we will split the equation into 2 separate equations for + and –

x= (3 + 10.44)/10

x = 13.44/10

x = 1.34

x = (3 - 10.44) / 10

x = -7.44 /10

x = -0.74

The two solutions are: x = 1.34 and x = -0.74