Flora M.

asked • 03/25/20

Heat of solution

Hi!

I will mix a salt with room-temperature water and 8 degree Celsius water. Then I will compare the heat of solution with each other. Does the temperature of the water from beginning affect how much the heat of solution and difference in temperature will be?

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J.R. S. answered • 03/25/20

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If I understand your question correctly, the answer would be "no". Water has a specific heat value of 4.184 J/g/degree or 1 cal/g/degree, and this value is the same if the water is 8ºC or 25ºC or any temperature at which the water is liquid. So, the temperature of the water shouldn't affect the amount of heat that will be transferred from a given set of circumstances provided no other variable is present. I'm not sure this answers your question, because I'm not positive exactly what you are asking.

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Flora M.

Thanks for answer! I was just wondering whether if the water is colder or not it will affect the enthalpy for solution/energy released/needed
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03/25/20

J.R. S.

tutor
No, it's just that the final temperature will be lower if the starting temp is lower. If a reaction has a certain enthalpy, it will transfer a certain amount of energy to the water and the temp will go up (if exothermic). The starting temp won't affect the amount of heat transferred. It will only affect the final temperature.
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03/25/20

Flora M.

Thank you!! :)
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03/25/20

Flora M.

One more question: what is the temp difference/energy needed is so much that the salt and water freezes. But the freezing will release energy itself? Will that affect the total amount energy released or will it be the same even if the water freezes?
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03/25/20

J.R. S.

tutor
Again, I'm sorry but I don't really understand what you're asking. If the water freezes, that is a phase change, and then you would have to invoke and use the ∆Hfusion. Does that answer your question?
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03/25/20

Flora M.

Yes that does answer (sorry my English is not so well). Thank you again very much
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03/25/20

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