Halston R. answered 03/22/20
Lifelong Student On A Journey -- Join Me
One way to solve this problem is to consider what the two gyms costs would look like as linear equations then to plot points (or enter data into a graphing calculator) with a cost over time (months) in mind.
Cost equals per month fee times number of months plus joining fee or, in standard form:
Gym one:
f(x) = 24x + 135
Gym two:
g(x) = 39x (+ 0 [since there was no joining fee])
The first month is easy.
Gym one's cost is just the joining fee plus the one month of membership fee. Or...
159 = 24(1) + 135
Gym two's cost is just that first month's membership fee. Or...
39 = 39(1) + 0
I did a second month [f(x) = 183 = 24(2)+135; g(x) = 78 = 39(2)], then a tenth month [f(x) = 375 = 24(10) + 135; g(x) = 390 = 39(10)] and saw that gym two's cost exceeded the cost of gym one, so I knew I'd gone too far. I went back one month and found the answer. By month nine, both gyms had equalized at $351.
If you'd graphed, you'd see the intersection at coordinate (9, 351).
Hope this helps!