The sum of three consecutive even integers is twice the first integer. Find the integers.

Answer 1

If the first even integer is: x

Then the next 2 consecutive integers would be: x+2, and x+4

The sum of them would be: x + (x + 2) + (x + 4)

and it is given that it is equal to twice the first number(which is x): 2 * x

Therefore:

x + (x + 2) + (x + 4) = 2x

3x + 6 = 2x

-x = 6

x = -6

Then the integers would be, -6, -6 + 2 and -6 + 4; or -6, -4, and -2.

Answer 2

2n-2 + 2n + 2n+2 = 4n - 4

2n = -4

n = -2

-6, -4, -2