Simon X. answered 03/18/20
Higher Level Math Tutor
Hi Emanuel,
We know the limit exists since the function is a quotient of two continuous functions and is therefore continuous, provided that the denominator is not equal to zero. The limit is 1. To see this, factor x6 out of the square root in the bottom expression to get
limx→∞ x3/(√(x6)√(1+3/x6))
=limx→∞x3/(x3√(1+3/x6))
=limx→∞1/√(1+3/x6)
=1/√(1+0)
=1.
Hope that helped.