Tanx + cotx = secx^2cotx

Arturo O. answered • 03/18/20

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I assume you meant to ask for a proof of this identity.

tanx + cotx = sinx/cosx + cosx/sinx = (sin²x + cos²x)/(cosx sinx) = 1/(cosx sinx)

= cosx / (cos²x sinx) = (1/cos²) (cosx / sinx) = sec²x cotx

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