J.R. S. answered 03/08/20
Ph.D. University Professor with 10+ years Tutoring Experience
C(s) + H2O(g) ⇌ CO(g) + H2(g)
0........8 atm..........0............0......initial
..........-x..............+x...........+x.....change
........8-x................x............x......equilibrium
Kp = 0.45 = (CO)(H2)/(H2O)
0.45 = (x)(x)/8-x
3.6 - 0.45x = x2
x2 + 0.45x - 3.6 = 0
x = 1.69 atm = partial pressure of H2