A rectangle has an area of 40 square units. The length is 6 units greater than the width. What are the dimensions of the rectangle?

Answer 1

L=length

W=width

L=6+W

A=Area

A=LW = (6+W)W= W² + 6W = 40

W² + 6W -40 = 0 This can be factored as 40 =4x10 and 10-4=6

(W+10)(W-4) = 0

set each factor = 0

W=4, -10 Ignore the negative solution

W=4

L=6+W=6+4 = 10

Width = 4, Length = 10

It's a 4x10 rectangle