The sum of the digits of a two-digit number is 11. The tens digit is one less than three times the ones digit. Find the original number

Answer 1

Let n be the tens digit and m be the ones digit.

n + m = 11

n = 3m - 1

Solve for n and m.

(3m - 1) + m = 11

4m = 12

m = 3

n = 11 - 3 = 8