Another way to solve is to use the point-slope formula.
y - y1 = m(x - x1)
y - 1 = 2(x - 1)
y - 1 = 2x - 2
y = 2x - 1
Malik C.
asked 03/05/20Write the equation in slope-intercept form of the line that has a slope of 2 and contains the point (1, 1).
Another way to solve is to use the point-slope formula.
y - y1 = m(x - x1)
y - 1 = 2(x - 1)
y - 1 = 2x - 2
y = 2x - 1
PETE C. answered 03/06/20
BS in Mathematics and Certified High School Math Teacher
Y = MX + B
M = 2 Given the SLOPE of 2.
(1,1) Given this point is on the line.
Now, all we have to do is determine what the Y-INTERCEPT B is, and we have our LINEAR equation,
the equation of a LINE.
Use (1,1) and plug into Y = MX + B to determine B. i.e. X=1 and Y=1.
Y = MX + B
1 = (2)(1) + B
1 = 2 + B
1 - 2 = 2 - 2 + B. Subtracting 2 from both sides.
-1 = B
Now we know M=2 and Y=-1, and we just plug those two values into Y = MX + B.
Y = 2X + (-1)
Y = 2X - 1 is the linear equation we are looking for.
CHECKING;
Let X=1 and plug into Y = 2X -1, and see if we get 1.
Y = (2)(1) - 1 = 2 - 1 = 1
Yes, the point(coordinate) (1,1) is on the line.
Hope this was helpful Malik.
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