f(5)=-2(5)^2+2(5)-3
(-2x25) + 10-3
-50 + 7 = -43
f(5)=-43
Madison J.
asked 03/03/20f(5)=-2(5)^2+2(5)-3
(-2x25) + 10-3
-50 + 7 = -43
f(5)=-43
Mark M. answered 03/03/20
Mathematics Teacher - NCLB Highly Qualified
f(5) = -2(52) + 2(5) + 3
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