
John M. answered 03/02/20
Math Teacher/Tutor/Engineer - Your Home, Library, MainStreet or Online
Y=-15.90x^2+ 110.48x +3.02
The initial velocity is 110.48 feet/second because the general equation is
Y = y0 + v0t +(1/2)at2
To catch the ball 6' above the ground, the equation is
6 = -15.90x^2+ 110.48x +3.02 yielding
0 = -15.90x^2+ 110.48x -2.98
Solving this yields x = 6.92 seconds for the fielder to get to the spot.
the maximum height of the hit ball is 188.9' plotting the parabola which opens downward.