270. mLof a 3.05 M NaNO3 solution

Question

Calculate the grams of solute needed to prepare

Answer 1

3.05 M = 3.05 moles NaNO3 per liter of solution

270 ml x 1 L/1000 ml x 3.05 mol/L = 0.8235 moles NaNO3 needed

0.8235 moles NaNO3 x 84.99 g/mol = 70.0 g NaNO3 needed (to 3 significant figures)

Answer 2

3.05 M = 3.05 moles NaNO3 per liter of solution

270 ml x 1 L/1000 ml x 3.05 mol/L = 0.8235 moles NaNO3 needed

0.8235 moles NaNO3 x 84.99 g/mol = 70.0 g NaNO3 needed (to 3 significant figures)