Find an equation of the tangent line to the graph of the function at the given point. f(x) = x + 1 x − 3 2 ; (7, 4)

Answer 1

I'm assuming there are parentheses around (x+1)(x-32); at point (7,4)

F(x) = x² - 31x -32

F'(x) = 2x - 31

F'(7) = 14 -31 = -17

The Point Slope Equation is y - y₁ = m(x - x₁)

y - 4 = -17(x -7)

y -4 = -17x + 119

y = -17x + 123