J.R. S. answered 02/24/20
Ph.D. University Professor with 10+ years Tutoring Experience
0.25 M = 0.25 mol NaCl/liter of solution.
Since you want only 0.500 L (500.0 ml x 1L/1000 ml), the number of moles NaCl needed will be...
0.25 mol/L x 0.5000 L = 0.125 moles
Molar mass of NaCl = 58.44 g/mol
Grams NaCl needed = 0.125 moles x 58.44 g/mol = 7.3 grams NaCl needed (to 2 significant figures) Ans C