help me with middle school math

Question

Mr.Jacobs has a $200 budget for school supplies. He purchased 12 reams of printer paper for $4 each and six packs of dry-erase markers for $3 each. He will spend the rest of his budget on calculators, which cost $8 each. Write and solve an inequality that represents the number of calculators he can purchase. Please you guys, anyone help me please?

Answer 1

So lets see how much paper and markers are going to cost.

12 * 4 = 48

6 * 3 = 18

Now to subtract these costs from the $200 budget:

48 + 18 = 66

200 - 66 = 134

So his remaining budget for calculators is $134. He can meet but not pass that with how many he does buy, so we have to use a less-than-or-equals-to sign:

8c ≤ 134

Now we divide by 8 because we want the calculators themselves, not the cost of them:

8c / 8 ≤ 134 / 8

c ≤ 16.75

You cannot purchase part of a calculator, so you need to round down:

c ≤ 16

Here's the mathematical process of what's going on:

8c + 12 * 4 + 6 * 3 ≤ 200

8c + 48 + 18 ≤ 200

8c + 66 ≤ 200

8c ≤ 134

c ≤ 16.75

c ≤ 16